Simple Harmonic Motion of a rolling ball

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SUMMARY

The discussion focuses on calculating the x component of a ball's position on a circular track with a radius of 0.61 m and a constant angular speed of 1.3 rad/s. The key equations used are x = A cos(θ) and θ = ωt, where A is the amplitude and ω is the angular speed. The user initially miscalculated the position by not converting time into radians, leading to incorrect results. Correct application of these formulas yields accurate position values at specified times of 2.6 s, 5.0 s, and 7.5 s.

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  • Understanding of angular motion and circular motion principles
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  • Knowledge of radians and their conversion from seconds
  • Ability to apply kinematic equations in rotational dynamics
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Homework Statement



A ball rolls on a circular track of radius 0.61 m with a constant angular speed of 1.3 rad/s in the counterclockwise direction.
A. If the angular position of the ball at t= 0 is \theta= 0, find the x component of the ball's position at the time 2.6 s. Let \theta= 0 correspond to the positive x direction.
B. Find the x component of the ball's position at the time 5.0 s.
C.Find the x component of the ball's position at the time 7.5 s

Homework Equations



x=Acos\theta
\theta=\omegat

The Attempt at a Solution


i used x=Acos\theta, using .61 the raduis for the A, amplitude, and the angular speed of the ball 1.3 ras/s for omega and the given times 2.6 it is not coming out right so i do not know what i am doing wrong.
 
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never mind.. i wasn't using radians.
 

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