Simple Harmonic Motion of a sewing machine

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Homework Help Overview

The problem involves a sewing machine needle that exhibits simple harmonic motion, characterized by an amplitude of 1.27 cm and a frequency of 2.55 Hz. The original poster seeks to determine the time taken for the needle to travel a distance of 11.43 cm.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between position and distance traveled in simple harmonic motion, with some questioning the validity of using the inverse cosine function for values outside the expected range.

Discussion Status

Some participants have offered guidance on understanding the distinction between position and distance traveled, suggesting that the original poster consider the number of full periods required for the motion. There is an ongoing exploration of the mathematical relationships involved.

Contextual Notes

There is a noted constraint regarding the maximum position values, as x must remain within the bounds of -1.27 cm and +1.27 cm. This has led to confusion regarding the calculations for the distance traveled.

rspbrrylmnd
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Homework Statement


A sewing machine needle moves up and down in simple harmonic motion with an amplitude of 1.27cm and a frequency of 2.55Hz. How long does it take to travel 11.43cm?


Homework Equations


x=A*cos(w*t)
w=2[tex]\pi[/tex]*f
w=2[tex]\pi[/tex]/T
T=1/f


The Attempt at a Solution


I can't determine the proper way to solve for t, since that's what the question is asking for. Every time I try to solve for t, the calculator gives me a 'math error' message and won't let me compute.

The answer is 0.878s, but I need to know how to get it.
 
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Every time the the needle goes through one full period it travels 4 amplitudes.
 
Welcome to PF!

Hi rspbrrylmnd! Welcome to PF! :smile:

(have a pi: π and an omega: ω :wink:)

Show us what you tried, including your wave equation. :smile:
 
Ok. I tried first to solve the equation for t before putting in any numeric values. Every time I would do that, though, I'd get the same equation.

x=A*cos(w*t)
x/A=cos(w*t)

From here, I assumed that the next logical step would be to take the inverse cosine of (x/A)

cos[tex]^{-1}[/tex](x/A)=w*t

Then I divided the entire thing by w to get:

[cos[tex]^{-1}[/tex](x/A)]/w=t

This is the same equation I come up with to solve for the time it takes for the needle to travel 11.43 cm. Whenever I plug in the numeric values, though, I can never calculate this equation because 11.43/1.47=9, and one cannot take the inverse cosine of anything larger than 1.

Is there a different relationship between these specific variables that I'm not aware of that would allow me to solve for the time? I'm simply at a loss and/or I have a mental block that is just not allowing me to see this problem from a different angle than by the process I have already tried.
 
x is the position and not the distance traveled.
x is always between -1.27 and + 1.27 cm.
You may start by calculating how many full periods (actually full half-periods) are required and then us the formula for the remainder. See post by Jebus_Chris too.
 
rspbrrylmnd said:
… Whenever I plug in the numeric values, though, I can never calculate this equation because 11.43/1.47=9, and one cannot take the inverse cosine of anything larger than 1.
nasu said:
x is the position and not the distance traveled.
x is always between -1.27 and + 1.27 cm.
You may start by calculating how many full periods (actually full half-periods) are required and then us the formula for the remainder. See post by Jebus_Chris too.
Jebus_Chris said:
Every time the the needle goes through one full period it travels 4 amplitudes.

:wink:
 

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