[SOLVED] Simple Harmonic Motion 1. The problem statement, all variables and given/known data A cheerleader waves her pom-pom in simple harmonic motion with an amplitude of 18.0 cm and a frequency of 0.850 Hz. Find (a) the maximum magnitude of the acceleration and of the velocity; (b) the acceleration and speed when the pom-pom's coordinate is x = +9.0 cm; (c) the time required to move from the equilibrium position directly to a point 12.0 cm away. (d) Which of the quantities asked for in parts (a), (b), and (c) can be found using the energy approach, and which ones cannot? Explain. 2. Relevant equations abs(a_max)= ω^2A, A = amplitude abs(v_max)=ωA ω=2πf, f=frequency a = -ω^2 sqrt(A^2 - x^2) 3. The attempt at a solution (a) ω=2π(0.85)= 5.34 rad/s abs(a_max)= (5.34)^2(0.18)= 5.13m/s^2 abs(v_max)= (5.34)(0.18) = 0.961 m/s (b) a = -(5.34)^2 sqrt((0.18)^2 - (0.09)^2) = -4.45m/s^2 speed = abs(v) = (5.34) sqrt((0.18)^2 - (0.09)^2) = 0.832 m/s I don't know how to approach (c) and (d).