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Eats Dirt
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Homework Statement
particle experiencing SHM with frequency f= 10 hz
find the displacement x at any time t for the following initial conditions.
@ t=0 x=0.25m v=0.1 m/s
Homework Equations
x=Asin(ωt+∅)
v=Aωcos(ωt+∅)
The Attempt at a Solution
So with frequency I find ω which then is subbed into the x=Asin(ωt+∅) @ t=0 to yield 0.25=Asin(∅).
I then get v=Aωcos(ωt+∅) and sub in for v and t and ω and get 0.25=A(20∏)cos(∅)
rearrange:
0.25/(20∏)=Acos(∅)
I then divide these equations by each other and rearrange to get:
arctan(50∏)= ∅
then with this I go back to 0.25=Asin(∅) and sub in ∅ rearrange to solve for A and its wrong! I get x=(0.16)sin(20∏t+1.56).
answer in book says x=0.25cos(20∏t)+0.00159sin(20∏t). it says also acceptable solutions would be x=0.25sin(20∏t+1.56) and its cos variant.
can someone please help I am confused about how they got this answer and how it is in that form.