- #1

sheepcountme

- 80

- 1

## Homework Statement

A small hole is drilled in a meter stick is to act as a pivot. The meter stick swings in a short arc as a physical pendulum. How far from the center of mass should the pivot point be for a period of 1.65 seconds?

## Homework Equations

Moment of inertia as given in book: I=(1/3)ml^2

T=2[tex]\pi[/tex][tex]\sqrt{}[/tex]I/mgh

(where t is period, I is moment of inertia, m is mass g is gravity of course, and h is the distance from the pivot oint to the center of mass)

## The Attempt at a Solution

I substituted the I in the second equation. The masses cancelled each other out in the square root, l is 1 since it is a meter stick and I used the given T so I end up with the equation...

1.65=2[tex]\pi[/tex][tex]\sqrt{}[/tex]((1/3)/gh)

And then I solved for h getting .493 meters but my book says this is incorrect.