The velocity of an object in simple harmonic motion is given by v(t)= -(0.269 m/s)sin(15.0t + 2.00π), where t is in seconds. What is the first time after t=0.00 s at which the velocity is -0.150 m/s?
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The Attempt at a Solution
so i tried finding the time by simply plugging -0.150 m/s in the equation v(t)= -(0.269 m/s)sin(15.0t + 2.00π) and solved for time i got a negative answer..when i tried to put that in it was wrong and so was the positive can someone tell me what i am doing wrong thankx