(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A massless spring is hanging vertically. With no load on the spring, it has a length of 0.22 m. When a mass of 0.68 kg is hung on it, the equilibrium length is 0.75 m. At t=0, the mass (which is at the equilibrium point) is given a velocity of 4.88 m/s downward.

At t=046s, what is the acceleration of the mass? (Positive for upward acceleration, negative for downward)

2. Relevant equations

[itex]\Sigma[/itex]F_{y}=-k(y_{eq}-y_{0})

[itex]\Sigma[/itex]F_{y}=ma_{y}

3. The attempt at a solution

The only two forces acting on the mass are the Tension from the spring and weight. So

T_{sm}-(mg)=ma_{y}

I am now stuck wondering if that was a good place to start. Is the traditional way to solve this problem to find the spring constant first?

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# Homework Help: Simple Harmonic Motion with Spring

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