Simple Harmonic Oscillator: From Hooke's Law to Harmonious Motion

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Bill Foster
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Homework Statement



Show simple harmonic motion starting from Hooke's Law.


The Attempt at a Solution



[tex]F=-kx[/tex]

[tex]=m\frac{d^2x}{dt^2}=-kx[/tex]

[tex]\frac{1}{x}\frac{d^2x}{dt^2}=-\frac{k}{m}[/tex]

[tex]=\frac{1}{x}\frac{d}{dt}\frac{dx}{dt}=-\frac{k}{m}[/tex]

[tex]\int\int\frac{1}{x}d\left(dx\right)=-\frac{k}{m}\int dt\int dt[/tex]

[tex]\int\frac{1}{x}dx=-\frac{k}{2m}t^2[/tex]

[tex]\ln\left(x\right)=-\frac{k}{2m}t^2[/tex]

[tex]x\left(t\right)=e^{-\frac{k}{2m}t^2}[/tex]

But it should be:

[tex]x\left(t\right)=e^{-i\sqrt{\frac{k}{2m}}t}[/tex]

I thought I knew how to do this. :redface:
 
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Well normally you could just put F=ma and then put it the form [itex]a= - \omega^2 x[/itex] and that would be sufficient to show SHM.


Else to solve the DE, you would need to know that the equation y''+ky=0 has solutions y1=cos(kt) and y2=sin(kt)
 
I want to solve the differential equation. But as you can see, somewhere I need to take the square root of the exponential argument.

Where, in my steps, did I miss that?
 
Nobody knows?
 
I don't see how to use this to get to the right answer, but:

[tex]\int\frac{1}{x}dx \neq \ln (x)[/tex]

[tex]\int\frac{1}{x}dx = \ln |x| + C[/tex]

So the derivation would continue:

[tex]\ln |x| + C =-\frac{k}{2m}t^2[/tex]

[tex]|x| = e^{-\frac{k}{2m}t^2 + C}[/tex]

Like I said, not sure how to use this, or if it helps. I could see squaring x, then taking the square root, in lieu of the absolute value signs, but, then, I don't see where the i comes out. Most of the derivations I've seen 'guess' at the solution of the 2nd order DE to be of the form [itex]a cos(\omega t)[/itex], and go from there.

I'm going to look at this more tomorrow, I can't believe I don't know either.
 
dotman said:
I'm going to look at this more tomorrow, I can't believe I don't know either.


[tex]m\frac{d^2x}{dt^2}=-kx \Rightarrow \frac{d^2x}{dt^2}+\frac{k}{m}x=0[/tex]


the auxiliary equation is r2+(k/m)=0 so r=±√(k/m)i

when you have roots in the form r=λ±μi what is the general solution x(t) equal to?