# Simple Index of Refraction Question - chart

1. Nov 4, 2008

### jcvince17

1. The problem statement, all variables and given/known data

what is the minimum value that the index of refraction can have?

2. Relevant equations

n1sin$$\Theta$$i = n2sin$$\Theta$$r

3. The attempt at a solution

my choices are:

A - between 0 and 1

B - +1

C - -1

D - 0

all listed values in my given chart are over 1. but that is not to say there is something else it can be. how can i determine this for sure?

2. Nov 4, 2008

### cepheid

Staff Emeritus
what is the definition of index of refraction?

3. Nov 4, 2008

### jcvince17

from my book:

" the index of refraction of an optical material, denoted as n, is the ration of the speed of light in a vacuum (c) to the speed of light in the material (v)

n = c / v "

ok so...light always travels more slowly in material....therefore it is always 1+

thanks for helping me find it. i told you it was simple...i was looking for an equation and not a definition.