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Simple Index of Refraction Question - chart

  1. Nov 4, 2008 #1
    1. The problem statement, all variables and given/known data

    what is the minimum value that the index of refraction can have?

    2. Relevant equations

    n1sin[tex]\Theta[/tex]i = n2sin[tex]\Theta[/tex]r

    3. The attempt at a solution

    my choices are:

    A - between 0 and 1

    B - +1

    C - -1

    D - 0

    all listed values in my given chart are over 1. but that is not to say there is something else it can be. how can i determine this for sure?
  2. jcsd
  3. Nov 4, 2008 #2


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    what is the definition of index of refraction?
  4. Nov 4, 2008 #3
    from my book:

    " the index of refraction of an optical material, denoted as n, is the ration of the speed of light in a vacuum (c) to the speed of light in the material (v)

    n = c / v "

    ok so...light always travels more slowly in material....therefore it is always 1+

    thanks for helping me find it. i told you it was simple...i was looking for an equation and not a definition.
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