EternityMech Messages 95 Reaction score 0 Thread starter Dec 7, 2011 #1 x+1/(x+2)(x+3) = A/x+2 +B/x+3 how do u calculate A and B ? nevermind i got it thanks. Last edited: Dec 7, 2011
mathman Science Advisor Homework Helper Messages 8,130 Reaction score 575 Dec 7, 2011 #2 R.H.S. = {A(x+3) + B(x+2)}/{(x+2)(x+3)} Therefore (assuming x+1 should be (x+1)): (A+B)=1 and (3A+2B)=1
R.H.S. = {A(x+3) + B(x+2)}/{(x+2)(x+3)} Therefore (assuming x+1 should be (x+1)): (A+B)=1 and (3A+2B)=1