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Simple Integral but unknown method

  1. Dec 7, 2011 #1
    x+1/(x+2)(x+3) = A/x+2 +B/x+3

    how do u calculate A and B ?

    nevermind i got it thanks.
    Last edited: Dec 7, 2011
  2. jcsd
  3. Dec 7, 2011 #2


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    R.H.S. = {A(x+3) + B(x+2)}/{(x+2)(x+3)}

    Therefore (assuming x+1 should be (x+1)): (A+B)=1 and (3A+2B)=1
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