- #1

semc

- 368

- 5

So i did this by parts and end up with -3( [tex]\frac{x}{e^x^/^3}[/tex] + [tex]\frac{3}{e^x^/^3}[/tex] ) x is from 0 to infinity. So for [tex]\frac{x}{e^x^/^3}[/tex] if we sub in infinity it would be infinity/infinity? How do we do that?