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Simple limit of sequences question.

  • Thread starter nothingkwt
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  • #1
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Let {An} = 2^n / n!

is it convergent or divergent and why?
 

Answers and Replies

  • #2
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Not right forum.
No effort shown.
 
  • #3
arildno
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Any suggestions yourself?
 
  • #4
tiny-tim
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Let {An} = 2n / n!

is it convergent or divergent and why?
(try using the X2 and X2 buttons just above the Rreply box :wink:)

tell us what you think, and why, and then we'll comment! :smile:

(and please use the homework forum in future)
 
  • #5
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Sorry I am new to this forum.

I thought of dividing both terms with the term that approached infinity more rapidly which was n!. which gave me 0, but then I saw that if 2n was actually 10n for example it would approach infinity more rapidly which would give me ∞ but I'm not entirely sure. So I got confused.
 
  • #6
tiny-tim
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I thought of dividing both terms with the term …
try dividing one term by the next term instead :smile:

(ie An/An+1)
 
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  • #7
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2*2*2*2*2... / n(n-1)(n-2)(n-3)...

So the limit goes to 0 it's clear now thanks.
 

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