Simple limit of sequences question.

1. Sep 20, 2013

nothingkwt

Let {An} = 2^n / n!

is it convergent or divergent and why?

2. Sep 20, 2013

johnqwertyful

Not right forum.
No effort shown.

3. Sep 20, 2013

arildno

Any suggestions yourself?

4. Sep 20, 2013

tiny-tim

(try using the X2 and X2 buttons just above the Rreply box )

tell us what you think, and why, and then we'll comment!

(and please use the homework forum in future)

5. Sep 20, 2013

nothingkwt

Sorry I am new to this forum.

I thought of dividing both terms with the term that approached infinity more rapidly which was n!. which gave me 0, but then I saw that if 2n was actually 10n for example it would approach infinity more rapidly which would give me ∞ but I'm not entirely sure. So I got confused.

6. Sep 20, 2013

tiny-tim

try dividing one term by the next term instead

(ie An/An+1)

7. Sep 20, 2013

nothingkwt

2*2*2*2*2... / n(n-1)(n-2)(n-3)...

So the limit goes to 0 it's clear now thanks.