1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Simple limit of sequences question.

  1. Sep 20, 2013 #1
    Let {An} = 2^n / n!

    is it convergent or divergent and why?
     
  2. jcsd
  3. Sep 20, 2013 #2
    Not right forum.
    No effort shown.
     
  4. Sep 20, 2013 #3

    arildno

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    Dearly Missed

    Any suggestions yourself?
     
  5. Sep 20, 2013 #4

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    (try using the X2 and X2 buttons just above the Rreply box :wink:)

    tell us what you think, and why, and then we'll comment! :smile:

    (and please use the homework forum in future)
     
  6. Sep 20, 2013 #5
    Sorry I am new to this forum.

    I thought of dividing both terms with the term that approached infinity more rapidly which was n!. which gave me 0, but then I saw that if 2n was actually 10n for example it would approach infinity more rapidly which would give me ∞ but I'm not entirely sure. So I got confused.
     
  7. Sep 20, 2013 #6

    tiny-tim

    User Avatar
    Science Advisor
    Homework Helper

    try dividing one term by the next term instead :smile:

    (ie An/An+1)
     
  8. Sep 20, 2013 #7
    2*2*2*2*2... / n(n-1)(n-2)(n-3)...

    So the limit goes to 0 it's clear now thanks.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Simple limit of sequences question.
  1. Simple Limits Question (Replies: 5)

Loading...