# Simple limit of sequences question.

Let {An} = 2^n / n!

is it convergent or divergent and why?

Not right forum.
No effort shown.

arildno
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Gold Member
Dearly Missed
Any suggestions yourself?

tiny-tim
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Let {An} = 2n / n!

is it convergent or divergent and why?

(try using the X2 and X2 buttons just above the Rreply box )

tell us what you think, and why, and then we'll comment! (and please use the homework forum in future)

Sorry I am new to this forum.

I thought of dividing both terms with the term that approached infinity more rapidly which was n!. which gave me 0, but then I saw that if 2n was actually 10n for example it would approach infinity more rapidly which would give me ∞ but I'm not entirely sure. So I got confused.

tiny-tim
Homework Helper
I thought of dividing both terms with the term …

try dividing one term by the next term instead (ie An/An+1)

• 1 person
2*2*2*2*2... / n(n-1)(n-2)(n-3)...

So the limit goes to 0 it's clear now thanks.