Simple limit of sequences question.

[nothingkwt]

Let {An} = 2^n / n!

is it convergent or divergent and why?

 

[johnqwertyful]

Not right forum.
No effort shown.

 

[arildno]

Any suggestions yourself?

 

[tiny-tim]

Let {A_n} = 2ⁿ / n!

is it convergent or divergent and why?

(try using the X² and X₂ buttons just above the Rreply box )

tell us what you think, and why, and then we'll comment!

(and please use the homework forum in future)

 

[nothingkwt]

Sorry I am new to this forum.

I thought of dividing both terms with the term that approached infinity more rapidly which was n!. which gave me 0, but then I saw that if 2ⁿ was actually 10ⁿ for example it would approach infinity more rapidly which would give me ∞ but I'm not entirely sure. So I got confused.

 

[tiny-tim]

I thought of dividing both terms with the term …

try dividing one term by the next term instead

(ie A_n/A_n+1)

 

[nothingkwt]

2*2*2*2*2... / n(n-1)(n-2)(n-3)...

So the limit goes to 0 it's clear now thanks.