Simple Pendulum: Explaining Why Time is Proportional to Route Length

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SUMMARY

The discussion centers on the relationship between the period of a simple pendulum and its length, specifically why the period (T) is proportional to the square root of the length (L). The key equation derived is T = 2π√(L/g), where g represents the acceleration due to gravity. The potential energy change of the pendulum bob, expressed as m g L (1 - cos θ), simplifies to m g L θ²/2 for small angles, while the kinetic energy change relates to m L² θ²/T². This analysis confirms that the period increases with the square root of the length, not merely the length itself.

PREREQUISITES
  • Understanding of basic physics concepts, particularly energy conservation.
  • Familiarity with pendulum mechanics and oscillatory motion.
  • Knowledge of trigonometric approximations for small angles.
  • Basic algebra for manipulating equations involving T, L, and g.
NEXT STEPS
  • Study the derivation of the pendulum period formula T = 2π√(L/g).
  • Explore the concept of simple harmonic motion and its characteristics.
  • Investigate the effects of varying angles on pendulum motion and period.
  • Learn about energy transformations in oscillatory systems, focusing on potential and kinetic energy.
USEFUL FOR

This discussion is beneficial for high school students studying physics, particularly those working on coursework related to pendulum motion and energy principles. It also aids educators looking to simplify complex concepts for younger learners.

joshd
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hey people. i am new to these forums.

i am doing some coursework on pendulums, for science. i have collected results, and have of course found t is proportional to route length. for my analysis, i need to say WHY, using some scientific knowledge.

so why is it? also, why is t proportional to ROUTE l, rather than just plain old l?


thanks in advance
 
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Here's one way to see the scaling. The change in potential energy of the pendulum bob as it oscillates is m g L (1 - \cos \theta) which is approximately m g L \theta^2/2 for small angles. Similarly, the corresponding change in kinetic energy is m v^2/2. But v = L \theta/ T where T is the period of the pendulum so the change in kinetic energy is about m L^2 \theta^2 /T^2.

Equating the two gives L^2 /T^2 = g L from which T scales as \sqrt {L/g}.
 
lol, sounds like ur doing the same piece of coursework that I had to do about a week ago.
 
did you include that ^^^ in the analysis? i semi-understand it, lol.

what are the moderators wanting to get an 8 in the analysis strand?
 
right, i am now writing the analysis, and i do not know what to put.

i was going to say t is proportional to route l because when the pendulum is longer, the bob has got furthere to travel. but then i remembered that below 10 degrees, it doesn't matter what angle away from the vertical you set the pendulum swinging, it will always have the same period.

so why is it that t is proportional to route l??
 
joshd said:
so why is it that t is proportional to route l??

That question has already been answered. And, BTW, it is "root" and not "route."
 
well, my teacher says that is too complicated for a GCSE coursweork assignment. to get full marks on the analysis part of the mark scheme i need to:

using evidence collected, draw appropriate conclusions, and explain them using detailed scientific knowledge.

how can i explain what i found, in a more simple way that is not A level stuff. basically, what i need to know is why does it take longer for a longer length, if it is not the distance the bob has to travel? (in simple terms)

sorry if i have not been clear, or have been a bit stupid, i am only 15.

(ps, thanks for correcting me on the root spelling error)
 
Last edited:

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