Simple Pendulum: Explaining Why Time is Proportional to Route Length

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Homework Help Overview

The discussion revolves around the relationship between the period of a simple pendulum and its length, specifically addressing why the period is proportional to the square root of the length. Participants are exploring the scientific principles underlying this relationship as part of a coursework assignment.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between potential and kinetic energy in the context of pendulum motion, questioning the implications of length on period. There are inquiries about simplifying complex explanations for a GCSE level understanding.

Discussion Status

The discussion is ongoing, with participants sharing insights and seeking clarification on the concepts involved. Some have provided mathematical reasoning, while others express the need for simpler explanations suitable for their coursework requirements.

Contextual Notes

There are references to specific educational standards and expectations for coursework analysis, indicating a need to align explanations with GCSE criteria. Participants also note the importance of using evidence from their experiments in their analyses.

joshd
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hey people. i am new to these forums.

i am doing some coursework on pendulums, for science. i have collected results, and have of course found t is proportional to route length. for my analysis, i need to say WHY, using some scientific knowledge.

so why is it? also, why is t proportional to ROUTE l, rather than just plain old l?


thanks in advance
 
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Here's one way to see the scaling. The change in potential energy of the pendulum bob as it oscillates is [itex]m g L (1 - \cos \theta)[/itex] which is approximately [itex]m g L \theta^2/2[/itex] for small angles. Similarly, the corresponding change in kinetic energy is [itex]m v^2/2[/itex]. But [itex]v = L \theta/ T[/itex] where T is the period of the pendulum so the change in kinetic energy is about [itex]m L^2 \theta^2 /T^2[/itex].

Equating the two gives [itex]L^2 /T^2 = g L[/itex] from which T scales as [itex]\sqrt {L/g}[/itex].
 
lol, sounds like ur doing the same piece of coursework that I had to do about a week ago.
 
did you include that ^^^ in the analysis? i semi-understand it, lol.

what are the moderators wanting to get an 8 in the analysis strand?
 
right, i am now writing the analysis, and i do not know what to put.

i was going to say t is proportional to route l because when the pendulum is longer, the bob has got furthere to travel. but then i remembered that below 10 degrees, it doesn't matter what angle away from the vertical you set the pendulum swinging, it will always have the same period.

so why is it that t is proportional to route l??
 
joshd said:
so why is it that t is proportional to route l??

That question has already been answered. And, BTW, it is "root" and not "route."
 
well, my teacher says that is too complicated for a GCSE coursweork assignment. to get full marks on the analysis part of the mark scheme i need to:

using evidence collected, draw appropriate conclusions, and explain them using detailed scientific knowledge.

how can i explain what i found, in a more simple way that is not A level stuff. basically, what i need to know is why does it take longer for a longer length, if it is not the distance the bob has to travel? (in simple terms)

sorry if i have not been clear, or have been a bit stupid, i am only 15.

(ps, thanks for correcting me on the root spelling error)
 
Last edited:

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