Simple problem calculate total Resistance parallel

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The problem involves calculating the total resistance of three resistors (10 ohms, 30 ohms, and 15 ohms) connected in parallel between points A and B, with a voltage of 12 volts across them. The formula used is 1/R = 1/R1 + 1/R2 + 1/R3, leading to the calculation of 1/R = 1/10 + 1/30 + 1/15. The solution simplifies to 1/R = 6/30, resulting in a total resistance (R) of 5 ohms. The calculations are confirmed to be mathematically correct, although some comments suggest that the approach may be overly complex. The final total resistance for the parallel resistors is 5 ohms.
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Homework Statement


I made this problem on my own.
resistors are
10 ohms
30 ohms
15 ohms

they are in parallel connections between A and B points
Voltage across A and B = 12 volts
calculate Rtotal

Homework Equations



1/ R = 1/ R1 ´+ 1/R2 + 1/R3

The Attempt at a Solution



1/R = 1/10 +1/30 + 1/15

1/R = 6/30 = 1/5

R/1 = 30/6 = 5/1
R= 5 ohms

If the inverse of R = 6/30

I guess then R itself should be inverse of (6/30) = 30/6

I think I got the same result with the laborious method.

1/R = 6/30 ]]]] * R
1= 6R/30 ]]]] * 30
30= 6R ]]]] / 6
30/6 = R
R= 5 ohms
 
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I get 5 Ohms also. :smile:
 
All what you write is mathematically correct but you just playing with algebra and the equation , especially in the last 5 lines of your post.
 
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