Confused by a High School Physics Problem? Discover the Missing Equation!

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The discussion centers around a challenging high school physics problem involving average speed and average velocity for a round trip at different speeds. The original poster struggled to find a third equation needed to solve for average speed, realizing that the distance cancels out in the calculations. The average speed was ultimately determined to be 3.75 m/s, regardless of the distance between points A and B. Participants expressed surprise that the problem was assigned without the teacher fully understanding it. The conversation highlights the importance of grasping fundamental concepts in physics education.
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I assigned a couple of problem to my students today without realizing that these would be too difficult for high school students. However, after starting the problem, I got stumped. I know I am missing something, but what is it? The problem reads as follows:

5. A person walks first at a constant speed of 5.00 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.00 m/s. What is
a. her average speed over the entire trip and
b. her average velocity over the entire trip?

Part b is simple, but 'a' is where I got stuck. You know delta x is the same, and you know that t1 and t2 will be different as well.

So, delta x = v1*t1, and x=v2*t2.

However this leaves us with three unknowns and two equations.

What am I missing for my third equation?

Thanks!
 
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x= distance traveled from A to B
v_1=5 m/s
v_2=3 m/s

x=5t_1
x=3t_2

t_1=x/5
t_2=x/3

avg. speed = distance/total time= 2x/(t_1 +t_2)=(2x)/(x/3+x/5)=3.75 m/s

one of your unknowns simply cancels out.

since the average speed will be the same no matter what the distance, it is unimportant what the distance between a and b are.
 
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Thanks,

I knew it was something like that.
 
Okay, so we are all relieved that the problem has a well-defined answer!

Are you telling us that you assigned this problem to your students without knowing how to do it yourself?


I agree that this problem is not too difficult for high school students- but I'm wondering about you!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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