- #1

- 273

- 5

Explain to me:

Why the 2πf came in front?

I lost touch and sort of forgot.

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- Thread starter lioric
- Start date

- #1

- 273

- 5

Explain to me:

Why the 2πf came in front?

I lost touch and sort of forgot.

Last edited by a moderator:

- #2

- 155

- 24

This is the ~~derivation~~ differentiation chain rule: [tex]\frac{df(g(x))}{dx}=\frac{df}{dg}\cdot\frac{dg}{dx}[/tex]

Edited by mentor...

Edited by mentor...

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- #3

- 273

- 5

could you please show me how this works with my example

- #4

- 155

- 24

- #5

jedishrfu

Mentor

- 12,691

- 6,552

##d/dt ( cos (2 * \pi * f * t) ) = ##

## = - sin ( 2 * \pi * f * t ) * d/dt ( 2 * \pi * f * t ) ##

## = - sin ( 2 * \pi * f * t ) * ( 2 * \pi * f ) ##

## = - ( 2 * \pi * f * t ) * sin ( 2 * \pi * f * t ) ##

- #6

mathman

Science Advisor

- 7,925

- 469

General formula. Let f'(x)=g(x), then f'(ax)=ag(ax).

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