Simple sample variance problem

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SUMMARY

The variance of the random variable Y, defined as Y = 4X + 2, where X follows the density function f(x) = 1/3 e^(-x/3) for x > 0, can be calculated using the formula Var(Y) = a^2 * Var(X). The expected value of X was determined to be 14 minutes, leading to a variance of 4 for X. Consequently, the variance for Y is computed as Var(Y) = (4^2)(4) = 64. The discussion clarifies that the correct formula for variance is E(X^2) - (E(X))^2, not E(X^2) - E(X).

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The length of time, in minutes, for an airplane to obtain clearance for takeoff is a random variable Y = 4X + 2, where X has the density function:

f(x) = 1/3 e^(-x/3) for x > 0

Find the variance of Y.

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I found the expected value of X to be 14 minutes, which was correct. This means the variance for X will be: E(X^2) - E(X) = 18 - 14 = 4. Will the following work for the variance?

Var(Y) = (4^2)(4) = 64.

If so, what does that mean to have a "negative" take off time?

Thanks for your help! :)
 
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The variance is NOT "E(X^2)- E(x)" it is E(X^2)- (E(x))^2.
 

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