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Precalculus Mathematics Homework Help
Solving x/2 in 3rd Quadrant: Cosx=-7/9
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[QUOTE="zaddyzad, post: 4499203, member: 404043"] [h2]Homework Statement [/h2] We have cosx = -7/9 in the third quadrant, and my question is how to find cos(x/2) and sin(x/2). I've tried using the sin^2x=1-cos2x/2 formula and its adjacent cosine formula. Is this the correct formula I should be using to get the answer for this question? [/QUOTE]
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Precalculus Mathematics Homework Help
Solving x/2 in 3rd Quadrant: Cosx=-7/9
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