JoeyBob
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Simple Wavelength Problem (wire of fixed length vibrating)
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Are you saying the official answer is 16 times the length of the wire? Bizarre.JoeyBob said:Homework Statement:: See attached
Relevant Equations:: wavelength = 2L/N
When the question says 8 antinodes, doesn't that mean N=8? but when I do 2L/8, I get 0.24.
To get the right answer you do 2LN, but that doesn't make sense to me for I thought the equation was 2L/N??
Frabjous
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I think the answer is wrong. There are 2 anti-nodes per wave length. Since you have 8 anti-nodes, there are 4 wavelengths on the wire. Therefore the wavelength is .24m which is what you got if you add units.
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JoeyBob
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Yeah the correct answer is 15.36, I guess its just wrong.haruspex said:Are you saying the official answer is 16 times the length of the wire? Bizarre.
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Safe guess.JoeyBob said:Yeah the correct answer is 15.36, I guess its just wrong.
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