I have been working on representing the powers of numbers as a summation.(adsbygoogle = window.adsbygoogle || []).push({});

This is as far as I have gotten.

Power: 2

[itex]m^2 = \sum_{n=1}^m \left(2n -1\right)[/itex]

Power: 3

[itex]m^3 = \sum_{n=1}^m \left(3n^2 -3n +1\right)[/itex]

Power: 4

[itex]m^4 = \sum_{n=2}^m \left[6*(4n-6) * \left(\sum_{a=1}^{m-n+1} a\right)\right] + m^2[/itex]

I wanted to know if it is possible to simplify the equation for the 4th and 3rd power of a number so that the highest power in the equation in 1.

Thanks

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# Simplify a summation and its product

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