I have been working on representing the powers of numbers as a summation.(adsbygoogle = window.adsbygoogle || []).push({});

This is as far as I have gotten.

Power: 2

[itex]m^2 = \sum_{n=1}^m \left(2n -1\right)[/itex]

Power: 3

[itex]m^3 = \sum_{n=1}^m \left(3n^2 -3n +1\right)[/itex]

Power: 4

[itex]m^4 = \sum_{n=2}^m \left[6*(4n-6) * \left(\sum_{a=1}^{m-n+1} a\right)\right] + m^2[/itex]

I wanted to know if it is possible to simplify the equation for the 4th and 3rd power of a number so that the highest power in the equation in 1.

Thanks

**Physics Forums - The Fusion of Science and Community**

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Simplify a summation and its product

Loading...

Similar Threads - Simplify summation product | Date |
---|---|

I Simplifying double summation | Jan 17, 2018 |

B Help simplifying an equation | Sep 23, 2017 |

How to simplify this summation to an incomplete gamma function | Apr 25, 2014 |

**Physics Forums - The Fusion of Science and Community**