Simplify Fraction with same term in Num and Dem, but.

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Homework Help Overview

The discussion revolves around simplifying a fraction involving algebraic expressions, specifically in the context of transfer functions for circuit design. Participants explore the factorization and simplification of fractions with common terms in the numerator and denominator.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the possibility of factoring out common terms in the denominator and consider alternative forms of the fraction. There is uncertainty about the simplification process and the effectiveness of different approaches.

Discussion Status

The discussion includes attempts to clarify the problem and explore various forms of the fraction. Some participants offer suggestions for factoring and changing the form, while others express uncertainty about the simplicity of the resulting expressions. There is acknowledgment of the specific context of transfer functions in circuit design.

Contextual Notes

Participants note a correction regarding the terms involved in the fraction, indicating a potential misunderstanding in the initial problem statement. The context of circuit design is highlighted as a relevant factor in the discussion.

zKarp
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Homework Statement


I'm having a brain fart, how do you factor/simplify a fraction such as \frac{ab}{ab+cd}
I keep thinking multiply by ab-bc but I'm not sure.
 
Last edited:
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zKarp said:

Homework Statement


I'm having a brain fart, how do you factor/simplify a fraction such as \frac{ab}{ab+bc}
I keep thinking multiply by ab-bc but I'm not sure.

Uh, the terms in the denominator have common factor b. Why don't you factor it out?
 
Dick said:
Uh, the terms in the denominator have common factor b. Why don't you factor it out?

I'm sorry I miss typed it after using latex format. It's suppose to be DC not BC.
 
zKarp said:
I'm sorry I miss typed it after using latex format. It's suppose to be DC not BC.

Then I don't think there is any form that is terribly much simpler than what you written. You can change the form, like to 1/(1+(cd)/(ab)), but I don't think the alternate forms are much simpler.
 
Dick said:
Then I don't think there is any form that is terribly much simpler than what you written. You can change the form, like to 1/(1+(cd)/(ab)), but I don't think the alternate forms are much simpler.

Thank you! This actually does. I should of stated I'm doing transfer functions for circuit design and that's the type of form desired. Thank you!
 
zKarp said:
Thank you! This actually does. I should of stated I'm doing transfer functions for circuit design and that's the type of form desired. Thank you!

Ok, so I helped by accident. You're welcome!
 

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