Simplify quotient of trignometric functions

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SUMMARY

The discussion focuses on simplifying the trigonometric expression \(\frac{\sin x + \tan x}{\csc x + \cot x}\). The user successfully transforms the expression into \(\frac{\sin x + \frac{\sin x}{\cos x}}{\frac{1}{\sin x} + \frac{\cos x}{\sin x}}\) and identifies the critical step of combining the numerator and denominator into single fractions before inverting the denominator and multiplying. The conclusion emphasizes the importance of simplification and factorization in solving trigonometric expressions.

PREREQUISITES
  • Understanding of basic trigonometric identities (sine, cosine, tangent)
  • Familiarity with the concepts of cosecant and cotangent functions
  • Knowledge of fraction simplification techniques
  • Ability to manipulate algebraic expressions
NEXT STEPS
  • Learn advanced trigonometric identities and their applications
  • Study techniques for simplifying complex fractions in algebra
  • Explore the use of trigonometric functions in calculus
  • Practice solving trigonometric equations and inequalities
USEFUL FOR

Students studying trigonometry, educators teaching mathematical concepts, and anyone looking to enhance their skills in simplifying trigonometric functions.

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Simplify \frac{sinx + tanx}{cscx + cotx}

I start with \frac{sinx + tanx}{cscx + cotx} = \frac{sinx + \frac{sinx}{cosx}}{\frac{1}{sinx} + \frac{cosx}{sinx}}

At this point I am stuck, I cannot see how we then get from \frac{sinx + \frac{sinx}{cosx}}{\frac{1}{cosx} + \frac{cosx}{sinx}} = \frac{sinx cosx + sin x}{1} \times \frac{sin x}{cos x}

What happened to the \frac{1}{cos x} from the denominator? I thought that would become \frac{cos x}{1} to give (sinx + \frac{sinx}{cosx}) \times ({\frac{cosx}{1} + \frac{sin x}{cos x})
 
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I think I figured it out. Needed to simplify the numerator and denominator into a single fraction, then invert the denominator and multiply. This was the step I was missing. Also needed to factorise the result of the multiplication.
 

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