- #1

- 2

- 0

Sinθ=

Cosθ=

Tanθ=

Cscθ=

Secθ=

Cotθ=

I believe the following are correct But I am not sure, Please give insight

Sinθ= 0/3

Cosθ= -3/3

Tanθ= 0/3

Cscθ= 3/0

Secθ= -3/3

Cotθ= 3/0

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter MattO7766
- Start date

- #1

- 2

- 0

Sinθ=

Cosθ=

Tanθ=

Cscθ=

Secθ=

Cotθ=

I believe the following are correct But I am not sure, Please give insight

Sinθ= 0/3

Cosθ= -3/3

Tanθ= 0/3

Cscθ= 3/0

Secθ= -3/3

Cotθ= 3/0

- #2

HallsofIvy

Science Advisor

Homework Helper

- 41,847

- 967

Also, you should know that 0/a= 0 and that a/0 does not exist.

- #3

- 489

- 0

First, the questions states that the point in question is P(-3, 0) only? So we are to assume that the origin is the starting point? But if that is the case, then all we have is a straight line down the negative x-axis. This would imply that the angle measured from the positive x-axis is simply [itex]\pi[/itex] or 180 degrees.

Is there another point that is given (your question states "pointS")?

Look here too: https://www.physicsforums.com/showthread.php?t=174661

Is there another point that is given (your question states "pointS")?

Look here too: https://www.physicsforums.com/showthread.php?t=174661

Last edited:

- #4

SammyS

Staff Emeritus

Science Advisor

Homework Helper

Gold Member

- 11,415

- 1,053

Sinθ=

Cosθ=

Tanθ=

Cscθ=

Secθ=

Cotθ=

I believe the following are correct But I am not sure, Please give insight

Sinθ= 0/3

Cosθ= -3/3

Tanθ= 0/3

Cscθ= 3/0

Secθ= -3/3

Cotθ= 3/0

Sinθ= 0/3 = 0

Cosθ= -3/3 = -1

Tanθ= 0/3 = 0

Cscθ= 3/0

Secθ= -3/3 = -1

Cotθ= 3/0

What is 3/0 ?

The others

Share: