- #1

- 2

- 0

Sinθ=

Cosθ=

Tanθ=

Cscθ=

Secθ=

Cotθ=

I believe the following are correct But I am not sure, Please give insight

Sinθ= 0/3

Cosθ= -3/3

Tanθ= 0/3

Cscθ= 3/0

Secθ= -3/3

Cotθ= 3/0

- Thread starter MattO7766
- Start date

- #1

- 2

- 0

Sinθ=

Cosθ=

Tanθ=

Cscθ=

Secθ=

Cotθ=

I believe the following are correct But I am not sure, Please give insight

Sinθ= 0/3

Cosθ= -3/3

Tanθ= 0/3

Cscθ= 3/0

Secθ= -3/3

Cotθ= 3/0

- #2

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 961

Also, you should know that 0/a= 0 and that a/0 does not exist.

- #3

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- 0

First, the questions states that the point in question is P(-3, 0) only? So we are to assume that the origin is the starting point? But if that is the case, then all we have is a straight line down the negative x-axis. This would imply that the angle measured from the positive x-axis is simply [itex]\pi[/itex] or 180 degrees.

Is there another point that is given (your question states "pointS")?

Look here too: https://www.physicsforums.com/showthread.php?t=174661

Is there another point that is given (your question states "pointS")?

Look here too: https://www.physicsforums.com/showthread.php?t=174661

Last edited:

- #4

SammyS

Staff Emeritus

Science Advisor

Homework Helper

Gold Member

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Sinθ= 0/3 = 0

Sinθ=

Cosθ=

Tanθ=

Cscθ=

Secθ=

Cotθ=

I believe the following are correct But I am not sure, Please give insight

Sinθ= 0/3

Cosθ= -3/3

Tanθ= 0/3

Cscθ= 3/0

Secθ= -3/3

Cotθ= 3/0

Cosθ= -3/3 = -1

Tanθ= 0/3 = 0

Cscθ= 3/0

Secθ= -3/3 = -1

Cotθ= 3/0

What is 3/0 ?

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