Simplifying Expression with Positive Variables a, b, and c | Step-by-Step Guide

  • Thread starter Thread starter BruceSpringste
  • Start date Start date
Click For Summary

Homework Help Overview

The problem involves simplifying an expression with positive variables a, b, and c, specifically x = ((ab√c)1/3-a(b2c)1/4)/(a3b2c)1/6. The original poster expresses uncertainty about how to begin the simplification process.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Some participants suggest starting by rewriting terms using laws of exponents, such as replacing √c with c^{1/2}. Others discuss factoring and canceling terms in the numerator and denominator.

Discussion Status

There is an ongoing exploration of different approaches to simplifying the expression. Some guidance has been provided regarding the use of exponent laws and factoring, but no consensus has been reached on a complete method.

Contextual Notes

The original poster notes the importance of the variables being positive, which may affect the simplification process, but further details on constraints or specific homework rules are not provided.

BruceSpringste
Messages
37
Reaction score
0

Homework Statement


Om a > 0, b > 0, c > 0, och x = ((ab√c)1/3-a(b2c)1/4)/(a3b2c)1/6

The Attempt at a Solution



I have no idea where to start. I understand the relevance of a,b and c being > 0 in order to simplify but other than that I am pretty much stuck!
 
Physics news on Phys.org
A first obvious step is to replace that [itex]\sqrt{c}[/itex] with [itex]c^{1/2}[/itex]. Then use the "laws of exponentials: [itex](abc^{1/2})^{1/3}= a^{1/3}b^{1/3}c^{1/6}[/itex], [itex]a(b^2c)^{1/4}= ab^{1/2}c^{1/4}[/itex] and [itex](a^3b^2c)^{1/6}= a^{1/2}b^{1/3}c^{1/6}[/itex]

So you have [tex]\frac{a^{1/3}b^{1/3}c^{1/6}- ab^{1/2}c^{1/4}}{a^{1/2}b^{1/3}c^{1/6}}[/tex]

Factor the largest power of a, b, and c in both terms in the numerator and cancel what you can with the denominator.
 
  • Like
Likes   Reactions: 1 person
\begin{align*}
\frac{\sqrt[3]{ab \sqrt{c}} - a \sqrt[4]{b^2 c}}{\sqrt[6]{a^3 b^2 c}}
\end{align*}

Wrote the equation in latex too, it was easier to see.
 
Alright that was easier than I previously thought! Thanks!
 

Similar threads

Replies
4
Views
2K
Replies
2
Views
2K
Replies
16
Views
2K
Replies
27
Views
6K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
7
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 7 ·
Replies
7
Views
7K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 21 ·
Replies
21
Views
2K