Simplifying Polynomial Fractions

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Homework Help Overview

The discussion revolves around simplifying a polynomial fraction involving variables and coefficients. The original expression presented is a rational function with a polynomial in the numerator and a polynomial in the denominator, which includes a potential factorization challenge.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants share their attempts to simplify the expression, noting various steps taken, such as multiplying by a common denominator to eliminate fractions and factoring terms. Some participants question the accuracy of the expressions and the implications of parentheses in the original problem setup.

Discussion Status

The discussion is ongoing, with participants providing insights into potential simplifications and corrections to earlier attempts. There is recognition of the need to clarify the original expression due to formatting issues, which may affect the simplification process.

Contextual Notes

There is mention of an extra parenthesis in the original expression that complicates the interpretation of the denominator. Participants are also considering the implications of certain terms being factored out and the restrictions that arise from these factorizations.

jumbogala
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Homework Statement


I need to simplify this:
((84/13)x4y - 4) / (-x + (21/13)x5)y)

Homework Equations


The Attempt at a Solution


I don't know if it can be simplified further. I can't factor anything out that will cancel. I multiplied both the top and the bottom by 13 to get rid of those fractions and got

(84x4y - 52) / (-13x + 21x5y) but that didn't make a solution jump out at me.

Help?
 
Last edited:
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I don't see anything either, but the -13 in the denominator should be -13x.
 
Oh right, thanks. I guess it can't be simplified then?
 
With a closer look, yes, it can be simplified a lot more.
[tex]\frac{84x^4y - 52}{(-13x + 21x^5y}~=~\frac{4(21x^4y - 13)}{x(21x^4y - 13)}~=~\frac{4}{x}[/tex]
This assumes, of course, that 21x4y - 13 != 0.
 
Here is what I got:
[(84x4y-52)/13] / (-xy + (21/13)x5y)
= [(84x4y-52)/13] / [(-13xy + 21x5y)/13]
= (84x4y-52) / (-13xy + 21x5y)
 
oNothinGo said:
Here is what I got:
[(84x4y-52)/13] / (-xy + (21/13)x5y)
= [(84x4y-52)/13] / [(-13xy + 21x5y)/13]
= (84x4y-52) / (-13xy + 21x5y)

But the numerator and denominator can be factored a bit more. Factor out the 4 in the numerator and the x in the denominator. You should get:

4(21x4y-13) / x(21x4y-13)

The (21x4y-13) from the top and the bottom divide out and you are left with 4/x. The restrictions would be (21x4y-13) is not equal to zero and x is not equal to zero.

Mark44 got it perfectly right.
 
Anakin_k said:
But the numerator and denominator can be factored a bit more. Factor out the 4 in the numerator and the x in the denominator. You should get:

4(21x4y-13) / x(21x4y-13)

The (21x4y-13) from the top and the bottom divide out and you are left with 4/x. The restrictions would be (21x4y-13) is not equal to zero and x is not equal to zero.

Mark44 got it perfectly right.
if you factor out x in the denominator, you will get x(21x4y-13y), not x(21x4y-13).
oh nvm.
Because Jumbogala wrote (-x + (21/13)x5)y), so I thought the y times (-x + (21/13)x5), which equals to (-xy + (21/13)x5y)
 
jumbogala said:

Homework Statement


I need to simplify this:
((84/13)x4y - 4) / (-x + (21/13)x5)y)

Homework Equations



The Attempt at a Solution


I don't know if it can be simplified further. I can't factor anything out that will cancel. I multiplied both the top and the bottom by 13 to get rid of those fractions and got

(84x4y - 52) / (-13x + 21x5y) but that didn't make a solution jump out at me.

Help?
In my earlier response, I simplified the final expression you showed, but didn't verify that it was the same as the original expression (it isn't). There is an extra right parenthesis in denominator of the first expression, so it's difficult to tell exactly what the original problem is. With that extra parenthesis, it's unclear whether that final y in the denominator multiplies only the x5 term or both terms in the denominator.

Can you clear this up for us?
 

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