Simplifying the Equation for Beginners

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SUMMARY

The discussion focuses on simplifying the equation for a pendulum system, specifically the expression 2π√{(Ml² + 2Mr²/5 + m(l-r)²/3) / (Ml + m(l-r)/2)g}. The user seeks guidance on identifying significant components of the equation for simplification. Key approximations include treating M-m as approximately M and simplifying (Ml + m(l-r)/2)g to Mlg. The values provided are M ≈ 10kg, m ≈ 20g, l = 227cm, and r = 6cm.

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This discussion is beneficial for physics students, educators, and anyone involved in mechanical engineering or dynamics who seeks to understand pendulum behavior and equation simplification techniques.

LENIN
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I have to find out how to make this simplification
[tex]2\pi \sqrt{ \frac {Ml^2+2Mr^2/5+m(l-r)^2/3} {(Ml+m(l-r)/2)g}} \approx 2\pi \sqrt{\frac{l}{g}(1+\frac{2r}{5l}-\frac{1m}{6M})}[/tex].

This is for a project I have to do, but I have never done any such simplifications before. I don't know which parts of the equation are important and which aren't. If it helps this are the values of the variables:

[tex]M\approx10kg[/tex]
[tex]m\approx20g[/tex]
[tex]l=227cm[/tex]
[tex]r=6cm[/tex]
 
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[tex](Ml+m(l-r)/2)g[/tex] would simplify to ~Mlg, in the denominator under the root.

(l-r)2 would simplify to l2 for very small r, otherwise l2-2rl since r2 would be small.

r/l = 6/227 = 0.026

m/M = 0.02/10 = 0.002 so M-m ~ M is a good approximation.
 
Thank you.
 

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