climbon
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Hi, I am trying to simplify this;
<br /> x \frac{\partial}{\partial x} W(x,y) - \frac{\partial}{\partial x} (xW(x,y))<br /> <br />
Am I correct in thinking I can do this with the product rule, as;
<br /> <br /> \frac{\partial}{\partial x} (xW(x,y)) = \left( \frac{\partial x}{\partial x}\right) W(x,y) + x \frac{\partial W(x,y)}{\partial x}<br /> <br /> \\<br /> <br /> =W(x,y) + x \frac{\partial W(x,y)}{\partial x}<br /> <br />
Giving the whole thing as;
<br /> <br /> x \frac{\partial W(x,y)}{\partial x} - W(x,y) - x \frac{\partial W(x,y)}{\partial x}=W<br /> <br />
Is this correct??
Thanks
<br /> x \frac{\partial}{\partial x} W(x,y) - \frac{\partial}{\partial x} (xW(x,y))<br /> <br />
Am I correct in thinking I can do this with the product rule, as;
<br /> <br /> \frac{\partial}{\partial x} (xW(x,y)) = \left( \frac{\partial x}{\partial x}\right) W(x,y) + x \frac{\partial W(x,y)}{\partial x}<br /> <br /> \\<br /> <br /> =W(x,y) + x \frac{\partial W(x,y)}{\partial x}<br /> <br />
Giving the whole thing as;
<br /> <br /> x \frac{\partial W(x,y)}{\partial x} - W(x,y) - x \frac{\partial W(x,y)}{\partial x}=W<br /> <br />
Is this correct??
Thanks