Single-slit diffraction diffraction pattern

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SUMMARY

The discussion centers on calculating the number of bright bands in a single-slit diffraction pattern, given that the 6th minimum occurs at an angle of 23° from the central maximum. The relevant equation is derived from the single-slit diffraction formula: sin θ = (n) λ/W, where λ is the wavelength of light, W is the slit width, and n is the minimum number. By establishing the ratio λ/W, one can determine the maximum number of bright bands on either side of the central band, which is closest to 14.

PREREQUISITES
  • Understanding of single-slit diffraction principles
  • Familiarity with the sine function and its properties
  • Knowledge of the relationship between minima and maxima in wave patterns
  • Basic algebra for solving equations with two variables
NEXT STEPS
  • Study the derivation of the single-slit diffraction formula
  • Learn how to calculate the wavelength of light using diffraction patterns
  • Explore the relationship between slit width and diffraction patterns
  • Investigate the effects of varying slit widths on the number of bright bands
USEFUL FOR

Students studying wave optics, physics educators, and anyone interested in understanding diffraction patterns and their calculations.

drawar
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Homework Statement


A single slit forms a diffraction pattern with monochromatic light. The 6th minimum of the
pattern occurs at an angle of 23° from the central maximum. The number of bright bands on
either side of the central band is closest to:
A) 16 B) 13 C) 14 D) 15 E) 17


Homework Equations


asin(theta)=mlambda


The Attempt at a Solution


Honestly I have no idea how to do this. Using the data given, I can only set up one equation with 2 unknowns, which is impossible to solve. On top of that I am unable to deduce a relationship between maxima and minima in a single-slit diffraction. I hope someone would throw me some light on this, thanks!
 
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drawar said:

Homework Statement


A single slit forms a diffraction pattern with monochromatic light. The 6th minimum of the
pattern occurs at an angle of 23° from the central maximum. The number of bright bands on
either side of the central band is closest to:
A) 16 B) 13 C) 14 D) 15 E) 17


Homework Equations


asin(theta)=mlambda


The Attempt at a Solution


Honestly I have no idea how to do this. Using the data given, I can only set up one equation with 2 unknowns, which is impossible to solve. On top of that I am unable to deduce a relationship between maxima and minima in a single-slit diffraction. I hope someone would throw me some light on this, thanks!

There is a formula governing the angle to each minimum which is something like

sin θ = (n) λ/W

where is the wavelength of light, and W is the width of the slit, and n is a count of the number of the minimum - so would be 6 here; for the 6th minimum.

Your formula looks like a transformation of that to W sin θ = (n)λ

Anyhow, once you have established the value of λ/W, you can work out the maximum value of (n) - since the sinθ has a maximum value of 1.
 

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