Single Slit Interference: Explaining the Phenomenon

Click For Summary
SUMMARY

The discussion focuses on the phenomenon of single slit interference, which occurs when waves pass through a slit and interfere with each other. It is established that the interference pattern results from wavelets originating from all points across the width of the slit, not just the endpoints. For calculating the intensity of the interference pattern, integration is necessary, while a simplified approach can be used to find the locations of minima. The phenomenon is applicable to various types of waves, including electromagnetic waves, water ripples, and sound waves, but requires slits larger than the wavelength to produce distinct interference patterns.

PREREQUISITES
  • Understanding of wave interference principles
  • Familiarity with basic optics concepts
  • Knowledge of wave properties, including wavelength
  • Ability to perform integration for wave calculations
NEXT STEPS
  • Study the principles of wave interference in detail
  • Learn about single slit diffraction patterns and their characteristics
  • Explore integration techniques for calculating wave intensity
  • Investigate the effects of slit width on interference patterns
USEFUL FOR

Students and educators in physics, particularly those studying optics, as well as anyone interested in the behavior of waves in various mediums.

wavingerwin
Messages
93
Reaction score
0
Single slit interference. ??

Can someone please explain to me about the single slit interference phenomenon?

My teacher said that after passing through the slit, it can be modeled that there are two wave source coming form each end of the "wall" which makes the slit. How can this actually happen?

Diagram:

| |
| |
--- top end of the 'wall'

>>> direction of wave

--- bottom end
| |
| |

And also, does this happen in every wave (e.g water ripples, sound waves) or just electromagnetic wave?

Thanks:smile:
 
Science news on Phys.org


The single-slit interference pattern is actually produced by interference among the waves that come from all points across the width of the slit (not just the endpoints). So in order to calculate the details of the interference pattern (i.e. the intensity at each point on the screen) you have to perform an integration. You can find the details in any optics textbook at the intermediate level or above, e.g. Hecht, Pedrotti, Meyer-Arendt, Strong, ...

For calculating only the locations of the minima (zero intensity) you can use a simplified non-calculus argument, which depends on exact cancellation of matched pairs of waves. This leads to a result which can be described using only the waves at the two edges of the slit, if I remember correctly.
 


does this happen in every wave (e.g water ripples, sound waves) or just electromagnetic wave?

Furthermore, what if the slit width is exactly the same as the wave's wavelength?
does interference can happen still? Or it only produces a continuous band with a maxima at the center?

Thanks
 


Single slit interference requires slits larger than a wavelength. Like jtbell states, a rough approximation is to consider that the wavelets passing though the middle of the slit are unperturbed, it is only the wavelets at the edges of the slit that will diffract and be the main contributors to an interference pattern. Once the slit's width becomes on the order of or smaller than the wavelength then you will reproduce a single slit diffraction pattern.
 


Once the slit's width becomes on the order of or smaller than the wavelength then you will reproduce a single slit diffraction pattern.

By "a single slit diffraction pattern" does it mean it produces a continuous band or a series of bright and dark fringes?

thanks
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 7 ·
Replies
7
Views
677
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 46 ·
2
Replies
46
Views
5K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 28 ·
Replies
28
Views
2K
  • · Replies 10 ·
Replies
10
Views
944