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HelpPlease27
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Homework Statement
A horizontal beam of laser light of wavelength 474 nm passes through a narrow slit that has width 5.80×10−2 mm . The intensity of the light is measured on a vertical screen that is 2.40 m from the slit.
Use the result of part A to estimate the width of the central diffraction maximum that is observed on the screen.
(Part A: What is the minimum uncertainty in the vertical component of the momentum of each photon in the beam after the photon has passed through the slit? I got this part.)
Homework Equations
$$\theta = \arcsin(\lambda/a)$$
$$y = d * \tan\theta$$
The Attempt at a Solution
I just used the two equations above first to get theta and then to get y and times y by two to get the central diffraction maximum but that's wrong. I'm missing at which part I'm supposed to use the minimum uncertainty. Can anyone explain, please?