Sir Isaac Newton Contest: Find the Minimum Length for a Safe Landing

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The problem involves a plane attempting a forced landing on a barge, with considerations of friction and momentum. The scenario includes a plane weighing 1.0*10^3 kg landing on a stationary barge weighing 2.0*10^3 kg, with the plane's braking force being a quarter of its weight. The objective is to determine the minimum length of the barge necessary for the plane to stop safely after touching down at a speed of 51 m/s.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the importance of the barge's motion and its effect on the plane's final velocity. Questions are raised about how to account for the barge's movement when calculating the plane's stopping distance and whether to treat the interaction as an elastic or inelastic collision.

Discussion Status

There is an ongoing exploration of the relationship between the plane's and barge's velocities. Some participants suggest using conservation of momentum to find the final velocity of the combined system, while others express uncertainty about how to set up the equations due to the inelastic nature of the collision. Multiple interpretations of the problem are being considered.

Contextual Notes

Participants note that the problem lacks sufficient information for a complete solution, particularly regarding the equations needed to relate the variables involved in the inelastic collision scenario.

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From the Sir Isaac Newton contest:

A 1.0*10^3 kg plane is tryin to make a forced landing on the deck of a 2.0*10^3 kg barge at rest on the surface of a clam sea. THe only frictional force to consider is between the plane's wheels and the deck, this braking force is constant and is equal to one quarter of the plane's weight. What must the minimum length of the barge be for the plane to stop safely on deck, if the plane touches down just at the rear end of the deck with a velocity of 5.0*10^1m/s towards the front of the barge?

Sorry, I don't quite understand this question. When the plane touches down, the barge will move as well, due to the frictional force. Then, how should I understand the motion of the plane? : should the plane be moving ahead at 51m/s, with deceleration determined by the braking force... or do we also have to take into consideration of the barge's motion as well?

Please, does someone have a solution for the problem? Thank you!
 
Last edited:
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The motion of the barge is important because when the plane has stopped on the deck of the barge the barge and plane are moving forward. So the final velocity of the plane is not zero. Figure out the final velocity of plane+barge using conservation of momentum then figure out the length of deck you need to stop.
 
Dick said:
The motion of the barge is important because when the plane has stopped on the deck of the barge the barge and plane are moving forward. So the final velocity of the plane is not zero. Figure out the final velocity of plane+barge using conservation of momentum then figure out the length of deck you need to stop.


If I want to determine the motion of the plane, with respect to the Earth, is its motion = 50m/s - decel due to friction force? or from here, do we still ahve to take into consideration the motion of the barge?
 
What you need to determine is the velocity of the plane relatively to the barge... The velocities in respect to the water can be determined by approaching the problem like an elastic collision...
 
Last edited:
Werg22 said:
What you need to determine is the velocity of the plane relatively to the barge... The velocities in respect to the water can be determined by approaching the problem like an elastic collision...

INELASTIC collision.
 
? How would you determine the velocities if it's inelastic? There wouldn't be enough information; one equation and two variables.
 
Inelastic collisions still conserve momentum.
 
Yes, hence our first equation... we are missing the other one.
 

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