1. The problem statement, all variables and given/known data Sketch the graph of y = sinx(1-cosx) over [-2pi, 2pi] 2. Relevant equations first derivative and second derivative 3. The attempt at a solution y' = cosxsinx 0 = cosxsinx x = pi/2, 3pi/2, 0, pi, 2pi I know I have the sin values right (the answers say the same) but the cos values in the answers are actually 2pi/3 for MAX and 4pi/3 for MIN. For that cosx would have to equal -1/2. I'm not sure how to get that ); Thank you!