- #1

Glissando

- 34

- 0

## Homework Statement

Sketch the graph of y = sinx(1-cosx) over [-2pi, 2pi]

## Homework Equations

first derivative and second derivative

## The Attempt at a Solution

y' = cosxsinx

0 = cosxsinx

x = pi/2, 3pi/2, 0, pi, 2pi

I know I have the sin values right (the answers say the same) but the cos values in the answers are actually 2pi/3 for MAX and 4pi/3 for MIN. For that cosx would have to equal -1/2. I'm not sure how to get that );

Thank you!