Sketching A Graph Using Differentiation

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The discussion focuses on the confusion regarding the steps in a differentiation problem related to sketching a graph. The main point of contention is the transition from step 4 to step 5, specifically how to factor out cos x correctly. There is uncertainty about whether to multiply (1 - 1/6) inside the brackets or to factor cos x out first. The calculations presented lead to different results, causing confusion about the correct approach. Clarification on these steps is essential for understanding the differentiation process in graph sketching.
themadhatter1
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Homework Statement



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Homework Equations





The Attempt at a Solution



I don't understand how they get from step 4 to step 5. Wouldn't you factor a cos x out of the brackets then have (\cos x)(1-\frac{1}{6}) to the left of the brackets. Then you can multiply the (1-\frac{1}{6}) inside the brackets.However that would yield [\frac{5}{6}+\frac{10}{3}\sin^2x] I don't understand how they are getting 1- (1/6) times the stuff inside the brackets.
 

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\cos x - \frac{1}{6}[(1-2\sin^2 x)\cos x - 2\sin^2 x\cos x]

= \cos x - \frac{1}{6}[ \cos x (1-2\sin^2 x - 2\sin^2 x) ]

= \cos x - \frac{1}{6} \cos x(1-2\sin^2 x - 2\sin^2 x)

= \cos x [ 1 - \frac{1}{6}(1-2\sin^2 x - 2\sin^2 x) ]
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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