How does the object slide down the surface (With friction negligible)
It's the Px vector component of the vector P that makes the object slides down along the surface , because the Py component cancels with the R vector , by using 2'nd motion law : P + R = m.a , we can break the P in to sub component vectors : Px + Py + R = m.a , the Py and R cancel each other's , so you'll get :
m.a = Px , that means that the object is moving in the direction of the vector Px so it's sliding down . look :
You'll need to be more specific. Tell us what you know and what you don't understand.
In the meantime, read this: Inclined Planes
We know that Object moves due to its Horizontal and vertical components right? So cancelling out means that it doesnt have any vertical component?
and how does the normal act when the object is moving?
.You have cancelled the Normal and Gravitational force only that that specific point right? But we have learned that gravity is always acting on that object...Wont it have any gravitational force when sliding?
it does, but its the component of the force and the magnitude of friction that opposes the direciton of motion on the slope that determines if it slides.
I didn't cancel the "GRAVITATIONAL" force , but the "Y COMPOONENT" of the gravitational force , which means that the x component is still remaining .
Yes, Lemme clear my doubt, The object is kept on an inclined surface....It wont go down because of the Normal force...And will slide down due to its horizontal component,right? But wont it have Normal foce on each point of its path while sliding after the initial Normal is cancellled out with the component AT THAT POINT?
the Normal force isn't restricted on the beginning point as you're saying , but it follows the object until the end of the path , and so do the gravity of course.
Yes right,So as the Normal acts on the objects continuously, as we have seen on the initial point the Normal Foce cancels out the gravitational force at that pont,So this process will happen on ecah point on the surface right?
yes exactly !
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