Slits per cm on diffraction grating

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Homework Help Overview

The problem involves determining the number of slits per centimeter on a diffraction grating, given that light of 650 nm can be observed in three orders. The context is within the subject area of optics, specifically diffraction and grating equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the diffraction grating equation and its relation to the problem, with some expressing uncertainty about how to start. Questions arise regarding the necessary information, such as the length of the grating, to determine slits per cm.

Discussion Status

Some participants have provided guidance on using the diffraction grating equation to relate various parameters, while others are exploring the implications of missing information. There is an acknowledgment of the complexity of the problem, but no explicit consensus has been reached.

Contextual Notes

Participants note the absence of the grating length as a potential constraint in solving the problem, which may affect the ability to calculate the number of slits per cm accurately.

msk172
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Homework Statement



Light of 650 nm can be seen in three orders in a particular grating. About how many slits per cm does this grating have?

Homework Equations



Yikes.

The Attempt at a Solution



Either this question is ridiculously hard resulting in me not even having a clue where to start, or it is so easy that I don't even deserve to get it right.. haha. If someone could just point me towards the right CONTINENT, I might have a chance.. heh. Thanks in advance.
 
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I understand that, but without knowing the length of the grating, how could one possible ascertain slits / cm?
 
The equation gives you the distance between adjacent slits. Take the reciprocal of that distance (in cm), and you get the number of slits per cm.
 
Got it. Ugh. Too many hours of looking at this screen. Thanks for your time.
 
You're welcome, no problem.
 

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