Which wagon reaches point B first and with the highest velocity?

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SUMMARY

In the discussion regarding two identical wagons approaching an inverted hill, it is established that the wagon traveling on the lower path reaches point B first and has a higher velocity at that point. Both wagons start at the same velocity and height, but due to the conservation of energy, the wagon on the lower slope experiences decreased potential energy, resulting in increased kinetic energy and velocity. Consequently, while both wagons achieve the same velocity at point B, the lower wagon arrives slightly sooner due to its advantageous path.

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Lets say two wagons is approaching a hill/slope which ends up at the exact same height as before the slope/hill. The wagons are identical and are traveling at the same velocity at point A (approaching the hill/slope). And the hill's/slope's shape is exactly the same but inverted.

Which if any, of the wagons reaches point B first, and which has the highest velocity at that point.

To me it seams logical that its the same for both wagons but as I remember it from a physics assignment in school a couple of years ago that isn't the case and the wagons time/velocity are different at point B.

If so, why?
 

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Looking at it in terms of "conservation of energy it is clear that the velocity of the two wagons will be the same at B- they are both at the same height they were before so have the same potential enter, thus the same kinetic energy and so the same velocity.

However, the lower wagon will have increased decreased potential energy, so increased kinetic energy and thus higher velocity while going through the while the first wagon has increased potential energy, so decreased kinetic energy and thus lower velocity while going over the hill. Afterwards, they will have the same velocity but the lower wagon will get to point B slightly sooner than the first wagon.
 
Thank you. It's nice too I still remember something at least. And that both that me and my colleague was "right" in a way.
 

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