Slope of a tangent From first principles

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SUMMARY

The discussion focuses on finding the slope of a tangent using first principles, specifically addressing the intersection of two graphs defined by the equation a² = 1/2 - a². The participant initially calculated the slope as -4 but later recognized the need to demonstrate that -4a² equals -1 at the point of intersection. The correct interpretation of the relationship between the slopes, m1 * m2 = -1, is crucial for solving the problem accurately.

PREREQUISITES
  • Understanding of calculus concepts, particularly derivatives and tangents.
  • Familiarity with algebraic manipulation and solving quadratic equations.
  • Knowledge of the geometric interpretation of slopes and points of intersection.
  • Basic proficiency in graphing functions to visualize intersections.
NEXT STEPS
  • Study the derivation of the slope of a tangent using first principles in calculus.
  • Explore the implications of the equation m1 * m2 = -1 in the context of perpendicular lines.
  • Investigate the method for finding points of intersection between two functions.
  • Practice solving similar problems involving quadratic equations and their graphical representations.
USEFUL FOR

Students studying calculus, particularly those tackling problems related to tangents and intersections of graphs, as well as educators looking for examples to illustrate these concepts.

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Homework Statement



# 23 http://img26.imageshack.us/img26/1008/questionsh.jpg

Homework Equations



m1 * m2 = -1

The Attempt at a Solution



i get -4 not sure what's wrong:

http://img4.imageshack.us/img4/6092/15608741.jpg
 
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In general 2a*(-2a) = -4a2

The question is show that if you have a value of a where a2=1/2-a2 (because this is where the two graphs intersect) then -4a2=-1
 
thats it forgot the POI, thank you.
 

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