Slope of N - t graph of radioactive decay

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SUMMARY

The discussion focuses on interpreting the slope of the graph representing radioactive decay, specifically the equation $$N=N_o e^{-\lambda t}$$. When plotting N against time (t), the slope is not directly defined, while plotting log N against t yields a slope of -λ. Understanding this distinction is crucial for accurately analyzing radioactive decay graphs.

PREREQUISITES
  • Understanding of radioactive decay principles
  • Familiarity with the equation $$N=N_o e^{-\lambda t}$$
  • Knowledge of logarithmic functions and their properties
  • Basic calculus concepts, particularly derivatives
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  • Study the implications of the decay constant (λ) in radioactive decay
  • Learn how to derive and interpret logarithmic transformations in data analysis
  • Explore graphical representations of exponential decay functions
  • Investigate the application of derivatives in physics and natural sciences
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Students and professionals in physics, particularly those studying radioactive decay, as well as educators looking to explain the relationship between exponential functions and their logarithmic counterparts.

songoku
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Homework Statement
Please see below
Relevant Equations
##N=N_o e^{-\lambda t}##
1713067012655.png


I am not really sure how to interpret the slope. The equation is:

$$N=N_o e^{-\lambda t}$$

If the graph is N against t, then what is the slope?

I can find the slope if the graph is log:
$$log N=log N_o -\lambda t$$

So if the graph is log N against t, then the slope is ##-\lambda##

But if the graph is N against t, I have no idea what the slope is.

Thanks
 
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Are you familiar with derivatives?
 
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Orodruin said:
Are you familiar with derivatives?
Yes. I understand your hint.

Thank you very much Orodruin
 

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