Values of a and b in pendulum equation?

[ajrvega22]

Ok guys so for my lab report I am given an equation of period=2pi(length/a)^b and through this equation and the slope and y-int of my log-log graph I am suppose to solve for the values of a and b. I know that taking the log of the equation gives me log(T)=log(2pi)+blog(L/a) and this relates to the slope intercept equation of y=mx+b where b is the slope. Therefore I know log(T) is y, blog(L/a) is mx and log(2pi) is b. I just can't figure out how to solve for the values of a and b?

 

[ehild]

Use that log(L/a)=log(L)-log(a). Write the equation for log(T) as function of log(L).

 

[brianeyes88677]

Spread your functions into logT=b*logL+log2π-b*loga. Compare to the regression line y=m*x+n from your experiment ,where b is the slope and log2π-b*loga is the intercept.