Slope of Tangent Line for f(x)=x^3+x at (2,10) | Algebraic Method

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SUMMARY

The discussion focuses on finding the slope of the tangent line for the function f(x) = x^3 + x at the point (2, 10) using an algebraic method. Participants emphasize the importance of calculating the derivative, f'(x), to determine the instantaneous rate of change at any point on the graph. The derivative is derived using the power rule, and the challenge presented involves simplifying the expression x^3 + x - 10 / (x - 2) to find the slope at x = 2. Ultimately, the derivative evaluated at x = 2 provides the exact slope of the tangent line.

PREREQUISITES
  • Understanding of calculus concepts, specifically derivatives
  • Familiarity with the power rule for differentiation
  • Knowledge of limits and their application in finding slopes
  • Basic algebraic manipulation skills
NEXT STEPS
  • Study the process of finding derivatives using the limit definition of a derivative
  • Practice simplifying rational expressions in calculus
  • Explore the application of the power rule in more complex functions
  • Learn how to graphically interpret the slope of tangent lines
USEFUL FOR

Students studying calculus, particularly those focusing on derivatives and tangent lines, as well as educators seeking to enhance their teaching methods in algebra and calculus.

Mejiera
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Homework Statement




find the slope of the tangent line of f at the given point.

Homework Equations



f(x)= x^3 + x at (2,10)

The Attempt at a Solution


I know how to get the answer using the power rule, but I want to know the algebraic way of doing it
I get stuck at x^3 + x - 10/ x -2 how do I get rid of the x-2 in the bottom ?
 
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f'(x) is the instantaneous rate of change at any x on the graph of f(x). In other words, f'(x) is the exact slope at any point on the graph of f(x). First, take the derivative of f(x). Then from there you can evaluate for any x (in your case x=2) to find the slope of your tangent line.
 

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