I can point you to an equation posted by George here
https://www.physicsforums.com/showthread.php?p=1543402#post1543402
\left( \frac{d\tau }{dt}\right) ^{2}=\left( \frac{3}{2}\sqrt{1-\frac{2M}{R}}-\frac{1}{2}\sqrt{1-\frac{2Mr^{2}}{R^{3}}}\right) ^{2}-v^{2},
If we consider the simple case of of a non rotating spherical body, then the -v^2 term on the end can be ignored and the equation simplifies to:
\left( \frac{d\tau }{dt}\right) =\left( \frac{3}{2}\sqrt{1-\frac{2M}{R}}-\frac{1}{2}\sqrt{1-\frac{2Mr^{2}}{R^{3}}}\right)
where \tau is the proper time of a clock located at a radius r inside the body of radius R and t is the clock rate at infinity.
Now if the clock is situated at the centre of the massive body, then r=0 and if the radius of the body is just slightly larger than Schwarzschild radius (9/8*2M) then:
\left( \frac{d\tau }{dt}\right) =\left( \frac{3}{2}\sqrt{1-\frac{2M}{(2M*9/8)}}-\frac{1}{2}\right)
\left( \frac{d\tau }{dt}\right) =\left( \frac{3}{2}\sqrt{\frac{1}{9}}-\frac{1}{2}\right)
\left( \frac{d\tau }{dt}\right) =\left( \frac{3}{6}-\frac{1}{2}\right) = 0
So there you have it. Frozen proper time, and the neutron star has not even formed a black hole yet. For radii less than 9/8 Rs but still greater than Rs, the equation gives negative proper time rates for the clock at the centre.