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Small mathematica operator question

  1. Oct 15, 2007 #1

    Quick question. In the ti89 i can do this:

    Answer = 3

    It works like x + 1 given x = 2...do 2+1 = 3. I'm not sure what the '|' operator would be called in this case...

    Anyway, is this shorthand possible in mathematica?

    like if i had: yy = E^T*C[1]+C[2], and i wanted to specify C[1]=1/6... what would do it?
    Last edited: Oct 15, 2007
  2. jcsd
  3. Oct 15, 2007 #2


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    Code (Text):
    yy = E^T*C[1]+C[2] /. { C[1] -> 1/6 }
     x + y /. {x -> 2, y -> 1}
    or just
    Code (Text):
    yy = E^T*C[1]+C[2] /. C[1]->1/6
    x+1 /. x -> 2
    if you have only one replacement.

    You can also do
    Code (Text):
    Block[ {C[1]=1/6},
    if you need the expression more often, but since you assign it anyway that's not necessary here (thought I generally prefer not assign variables)
  4. Oct 15, 2007 #3
    Thx that'll do :cool:
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