Insights Blog
-- Browse All Articles --
Physics Articles
Physics Tutorials
Physics Guides
Physics FAQ
Math Articles
Math Tutorials
Math Guides
Math FAQ
Education Articles
Education Guides
Bio/Chem Articles
Technology Guides
Computer Science Tutorials
Forums
Trending
Featured Threads
Log in
Register
What's new
Search
Search
Search titles only
By:
Menu
Log in
Register
Navigation
More options
Contact us
Close Menu
JavaScript is disabled. For a better experience, please enable JavaScript in your browser before proceeding.
You are using an out of date browser. It may not display this or other websites correctly.
You should upgrade or use an
alternative browser
.
Forums
Physics
Classical Physics
Electromagnetism
Small question about maxwell's equation curl of H
Reply to thread
Message
[QUOTE="Charles Link, post: 6004747, member: 583509"] You will see a similar thing in electrostatics with ## -\nabla \cdot \vec{P}=\rho_p ##, and ## \nabla \cdot {E}=\frac{\rho_{total}}{\epsilon_o} ##, where ## \rho_{total}=\rho_{free}+\rho_p ## The equation ## \nabla \cdot \vec{D}=\rho_{free} ## is a result of using the definition ## \vec{D}=\epsilon_o \vec{E}+\vec{P} ##. Upon taking the divergence of both sides of the equation, the result ## \nabla \cdot \vec{D}=\rho_{free} ## follows. There is a surface polarization charge density ## \sigma_p=\vec{P} \cdot \hat{n} ##, but this is all part of ## -\nabla \cdot {P}=\rho_p ## by applying Gauss' law to the discontinuity in ## \vec{P} ##. ## \\ ## And it may also interest you that there is a "pole" model of magnetostatics, analogous to the electrostatic "pole" method, that works with magnetic "pole" density ## \rho_m=-\nabla \cdot \vec{M} ##, where the magnetic "poles" are sources of ## \vec{H} ## using the inverse square law, and magnetic surface currents ## \vec{K}_m ## are ignored. The "pole" method also uses the equation ## \vec{B}=\mu_o (\vec{H}+\vec{M} ) ##. Very surprisingly, both methods get the exact same answer for the magnetic field ## \vec{B} ##. In this "pole" model, free currents in conductors are also considered to be sources of ## \vec{H} ##, with the ## \vec{H} ## determined by a Biot-Savart type equation, but with ## \vec{H}=\frac{\vec{B}}{\mu_o} ##. [/QUOTE]
Insert quotes…
Post reply
Forums
Physics
Classical Physics
Electromagnetism
Small question about maxwell's equation curl of H
Back
Top