Solenoid flux-emf-current problem

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Homework Help Overview

The problem involves a solenoid inductor with given values for emf, current change rate, and magnetic flux per turn. The objective is to determine the number of loops in the solenoid based on these parameters.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to relate two different cases of the solenoid using equations but expresses difficulty in progressing due to a lack of information about the solenoid's radius. Other participants suggest relevant equations and explore the relationship between magnetic flux and the number of turns.

Discussion Status

Participants are actively discussing the equations that may be relevant to the problem. Some guidance has been offered regarding the equations needed, but there remains uncertainty about specific parameters such as the solenoid's radius, which is impacting the ability to proceed with calculations.

Contextual Notes

There is a noted constraint regarding the missing radius of the solenoid, which affects the calculation of surface area and the application of the equations discussed.

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Homework Statement


A solenoid inductor has an emf of 0.20 V when the current through it changes at the rate 10.0 A/s. A steady current of 0.10 A produces a flux of 5.0 microWb per turn.

The number of loops in the solenoid is the value which needs to be found.

Homework Equations





The Attempt at a Solution


I have been going through this problem for a good hour, and am simply stuck. Clearly there are two different cases which are presented for the same solenoid, which clearly means that each case needs to be plugged into an equation and these two equations must be related through an unknown variable. Please state any equations you may use in the solving of this problem, I have two pages of fruitless work in front of me.
 
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[tex]\phi=BA[/tex]

[tex]B= \frac{\mu NI}{l}[/tex]

N=No. of turns
l=length.

You'll need those 2.
 
The problem I keep running into with the first equation you listed is that I do not know what the radius of the solenoid is, and as a result I am unable to determine the surface area of the solenoid.
 
Combining the 2 equations you'll get

[tex]\phi = \frac{\mu NIA}{l}[/tex]


Dividing both sides by N


[tex]\frac{\phi}{N}=\frac{\mu IA}{l}[/tex]

Can you use the second line of the question to find a value for the ratio of [itex]\frac{A}{l}[/itex]?


Then use the fact that

[tex]E=\frac{d}{dt}{\phi}[/tex]

or simply

[tex]E=\frac{\phi}{t}[/tex]
 

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