Solid insultaing sphere electric field

  • #1

Homework Statement


A solid insulating sphere of radius R carries a charge per unit volume of p. Use Gauss' law to find an expression for the eletric field on a spherical surface of radius R/2 ie: inside the sphere.


Homework Equations


Gauss' Law = (Net Flux = Q / Eo)

Volume of a Sphere = (4/3)(pi)(R^3)


The Attempt at a Solution


I simply combined Gauss' Law and the volume of the sphere to get,

E = (4Q) / [(3)(pi)(Eo)((R/2)^3)]

That seems to easy though have I missed something?
 

Answers and Replies

  • #2
Doc Al
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I simply combined Gauss' Law and the volume of the sphere to get,

E = (4Q) / [(3)(pi)(Eo)((R/2)^3)]
Not sure what you did here. What's Q? Express the charge within the gaussian surface in terms of ρ. How do you calculate the flux?
 

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