Solid Mechanics, calculating reaction forces and M(X) for a cantilever thing

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SUMMARY

The discussion focuses on calculating reaction forces and the moment function M(X) for a cantilever beam subjected to a moment M_0. The participant correctly derives the reaction force on the right side as r_y = -M_0/L by setting the sum of moments to zero. The moment function is expressed as M(X) = M_0 - (M_0/L) * (L-X). Clarifications are made regarding boundary conditions, with the participant uncertain about their application, particularly concerning the left support's ability to resist vertical forces.

PREREQUISITES
  • Understanding of solid mechanics principles, specifically cantilever beam analysis.
  • Familiarity with moment calculations and equilibrium equations.
  • Knowledge of boundary conditions in structural analysis.
  • Proficiency in interpreting reaction forces in static systems.
NEXT STEPS
  • Study the principles of cantilever beam design and analysis.
  • Learn about boundary conditions and their implications in structural mechanics.
  • Explore the concept of moment distribution in beams under various loading conditions.
  • Investigate the effects of different types of supports on reaction forces and moments.
USEFUL FOR

Students and professionals in engineering fields, particularly those specializing in structural and mechanical engineering, will benefit from this discussion as it addresses fundamental concepts in analyzing cantilever beams and their reaction forces.

PenTrik
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Homework Statement


ProblemCheck.jpg



Homework Equations


M = F * D


The Attempt at a Solution



For a, I need to find the reaction force on the right side. So what I first did was make the sum of the moment on the left equals zero.
0 = M_0 + r_y * L.
r_y = \frac{-M_0}{L}
I think this is right.

When you take net sum of the moments, then there should be no moment imparted by the wall correct? I'm not sure.

For my M(X) term, assuming that I have my reaction forces on the right correct, it should be
M_0 - \frac{M_0}{L} * (L-X)

As for the boundary conditions, I'm not really sure what they should be. I'm pretty sure they're supposed to mean v(0) = v(L) = 0

I'm not sure if this is correct at all.
 
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The support on the left is unusual, if not impractical, but I interpret it as being a normal encastre support resting rx and moment, but with no vertical restraint. Therefore ry must be zero. Your ry=M0/L is correct for a left hand support resisting ry but not rx. Are you sure the diagram is correct?
If the left support is capable of resisting moment then your assumption that it is zero is not correct. If the left support resists only rx, then the whole thing is a mechanism, with rotation about the right support.
 

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