Solid Mechanics: Calculating Stress for Aluminium & Steel

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Discussion Overview

The discussion revolves around calculating stress (\(\sigma\)) for aluminum and steel in a solid mechanics context. Participants explore the relationship between stress, strain, and material properties, while considering the effects of applied forces and constraints on deformation.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant suggests using the formula \(\sigma = F/A\) but expresses uncertainty about incorporating material types and elasticity, indicating a potential use of Hooke's law.
  • Another participant points out that the rigid top plate imposes constraints on deformation, prompting a discussion about the strains in both steel and aluminum.
  • There is a proposal that aluminum and steel might have the same strains, leading to a calculation of force ratios based on the area of the rigid plate.
  • A participant formulates equations relating stress and strain, using the modulus of elasticity for both materials, but notes the presence of multiple unknowns in their equations.
  • One participant questions whether stress is influenced by the height of the element, to which another participant agrees that it appears not to be the case.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between stress and strain for aluminum and steel, with some proposing that strains are equal while others do not explicitly agree. The discussion remains unresolved regarding the implications of height on stress calculations.

Contextual Notes

There are unresolved assumptions regarding the strains and the specific conditions under which the materials are analyzed. The relationship between forces, areas, and the constraints imposed by the rigid plate is also not fully clarified.

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now i am looking for the stress [tex]\sigma[/tex] for the aluminium and for the steel
i would want to say simply [tex]\sigma[/tex]=F/A but i need to somehow take into account the types of materials and their elasticity,
i think that hookes law could help me here but i don't know the strains
also how do i take the volume into account? the only equation i have for volume is [tex]\Delta[/tex]=[tex]\epsilon[/tex]x + [tex]\epsilon[/tex]y + [tex]\epsilon[/tex]z, but i doubt that's going to help
 
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You know a little about the strains, since the rigid top plate supplies a constraint on the components' deformation. What can you say about the strain of the steel and aluminum?

Each component will have its own stress, cross-sectional area, and force. Can you relate the forces to the applied load?
 
i would think that the aluminium and steel have the same strains.
i can find the ratio of forces on each material as their area of the rigid plate? is this correct?

F(Al) = 4P/7
F(Steel)= 3P/7

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can i say that since i only have forces on the y axis

[tex]\sigma[/tex]=[tex]\epsilon[/tex]*E

now since the strains are the same

[tex]\sigma[/tex]Al=[tex]\epsilon[/tex]*70*109
[tex]\sigma[/tex]Steel=[tex]\epsilon[/tex]*200*109

now i have t equations and 3 unknowns, but i know

[tex]\sigma[/tex]Al*2*10-3 + [tex]\sigma[/tex]Steel*1.5*10-3=385*103



thanks for the help
 
does that mean that the stress has nothing to do with the height of the element
 
That's what it looks like.
 

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