Calculating stress and strains for beam of applied force

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SUMMARY

This discussion focuses on calculating stress and strain in a rectangular beam subjected to an applied force. The primary equation used is $$\sigma = F/A = \frac{F}{wh}$$, where A is the area perpendicular to the applied force. When the force is applied at both ends, the internal force must be considered, leading to a potential confusion about whether to use F or 2F in calculations. Additionally, the discussion raises questions about calculating stress and strain when the force is applied in the [111] direction, indicating a need for clarity on the nature of stress in this orientation.

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  • Understanding of basic mechanics of materials
  • Familiarity with stress and strain concepts
  • Knowledge of free body diagrams
  • Ability to interpret directional forces in three-dimensional space
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  • Study the derivation of stress formulas in beam theory
  • Learn about the implications of applying forces at different orientations, specifically in the [111] direction
  • Explore the concept of internal forces in beams and their relation to external forces
  • Investigate the effects of boundary conditions on stress distribution in beams
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jhartc90
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Homework Statement


If I consider a force, which is applied to both ends of a rectangular beam to its cross section with dimensions w (width) and h (height) and I know the length of the beam is l and the force is parallel, how can I calculate the stress?

Also, what if the force were parallel to the [111] direction? How could I calculate the stress and strain considering the force is not parallel?

Homework Equations


For the first part, I think I would just use:
$$\sigma = F/A = \frac{F}{wh}$$

I now that A is the area perpendicular to the applied force.
But do I need to anything specific to account for the fact that it is applied at both ends?

Also, when the force applied is in the [111] direction, I am not sure how to calculate the stress and strain.

The Attempt at a Solution


As per the relevant equations, I show my attempt. I just use
$$\sigma = F/A = \frac{F}{wh}$$
for the first part. Not sure if it should be 2F since the force is applied on both ends?

I am not sure about how to calculate stress and strain when the force is parallel to the [111] direction. Any ideas? How do I calculate the area perpendicular to the applied force in [111] direction (just in variables).
 
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jhartc90 said:

Homework Statement


If I consider a force, which is applied to both ends of a rectangular beam to its cross section with dimensions w (width) and h (height) and I know the length of the beam is l and the force is parallel, how can I calculate the stress?

Also, what if the force were parallel to the [111] direction? How could I calculate the stress and strain considering the force is not parallel?

Homework Equations


For the first part, I think I would just use:
$$\sigma = F/A = \frac{F}{wh}$$

I now that A is the area perpendicular to the applied force.
But do I need to anything specific to account for the fact that it is applied at both ends?

Also, when the force applied is in the [111] direction, I am not sure how to calculate the stress and strain.

The Attempt at a Solution


As per the relevant equations, I show my attempt. I just use
$$\sigma = F/A = \frac{F}{wh}$$
for the first part. Not sure if it should be 2F since the force is applied on both ends?

I am not sure about how to calculate stress and strain when the force is parallel to the [111] direction. Any ideas? How do I calculate the area perpendicular to the applied force in [111] direction (just in variables).
When you apply a force F perpendicular to the cross section (parallel to the axial length of the beam) , the reaction force at the other end must be F in the opposite direction, from equilibrium considerations. Thus, the net external force on the beam is zero. But, the internal force in the beam is non-zero, and that internal force perpendicular to the cross section is the force to use when determining the axial stress. So if you draw a free body diagram cutting through the beam, is that internal force F or 2F?
For the second part, I don't know what you mean by the [111] direction, you mean perpendicular to the length? That's a stress of a different nature.
 

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