- #1

Bellwether

- 5

- 0

## Homework Statement

Find the volume of a solid created when the area between the function y=x^2+1 and the x-axis (for 0<x<2) is rotated about the line y=-2.

## Homework Equations

Vs = ∏*r^2*h

## The Attempt at a Solution

I can't seem to set this up correctly and am thrown by the inner radius being the x-axis. I originally set up the integral as : Int {0,2} ∏((x^2+1) + 3)^2 dx

I think this creates a full solid around y=-2 -- would I just want to add 1 to the radius instead of 3?

Many thanks!